sci.math Google Group

Palestinians Under Attack

smam...@gmail.com — Fri, 09 Jan 2009 00:55:20 UT

Palestinians Under Attack
تعرض الشعب الفلسطيني في غزه لظلم رهيب على ايدي القوات الاسرائيليه
Palestinians are exposed for horrible unfairness at the hands of
Israeli forces.
حصار دام لشهور .. انقطاع للكهرباء دام لشهور..

Study: Black Holes Seem to Form Before Galaxies

s...@sdrodrian.com — Fri, 09 Jan 2009 00:01:58 UT

Study: Black Holes Seem to Form Before Galaxies
January 7, 2009 from the A.P.
WASHINGTON (AP) -- When galaxies initially formed,
they weren't the first in the cosmic neighborhood. The
supermassive black holes, which reside at the center
of galaxies, probably moved in first, a new astronomy
study suggests.

Extending a function from the boundary of an open set

p...@grex.org (Graven Water) — Thu, 08 Jan 2009 23:33:17 UT

see [link]
Laura
If you like reading the source better it is below:
I'm reading Lars Hormander's book on multivariable complex
analysis and I'm puzzled by something.
In Theorem 2.3.2' the suppositions are:
Let $\Omega$ be a bounded open set in $\mathbf C^n$, $n>1$, such that the

first euler's identity

lukaszgoo...@o2.pl (lg) — Thu, 08 Jan 2009 21:24:58 UT

hi,
could anybody help me to prove the first euler's identity?
the equation is:
(1+x)(1+x^3)(1+x^5).... = sum(from k=1 to infinity) ( ( x^
( k^2 ) ) ) / ( (1-x^2)(1-x^4)(1-x^6)... )
the second equation is similar:
(1+x^2)(1+x^4)(1+x^6).... = sum(from k=1 to infinity) ( ( x^( k(k
+1) ) ) ) / ( (1-x^2)(1-x^4)(1-x^6)... )

Some formulas of varieties

sanchopanch...@web.de — Thu, 08 Jan 2009 21:24:37 UT

Hello,
let R be a commutative ring with unit and I, J two ideals in R. I
think that I have figured out that the relation
V(I*J)=V(I/\J)=V(I) \/ V(J)
holds. Is this really true? I mean, the Chinese remainder theorem says
that I*J=I/\J if I+J=R and with the above relation one gets in any
case rad(I*J)=rad(I/\J) if R is a polynomial ring over an

Does x^2+y^2=z^50 have integer solutions?

alvarez.torr...@gmail.com — Thu, 08 Jan 2009 20:49:39 UT

Does x^2+y^2=z^50 have integer solutions >0?

Re: Aether Displacement

dolomi...@hotmail.com (foolsrushin) — Thu, 08 Jan 2009 20:11:25 UT

Amazing discussion, yet Bell's Theorem? Add a dimension and you are
knocking on your own door and let yourself in - and not just now.
Really upper dimensional stuff might be bizzare, to say the least, and
would need a lot more energy to manifest itself.
Thin, silly beings attempted to abduct a farmer by lifting him up into

Stuck on modal logic proof

sg...@hotmail.co.uk (Rotwang) — Thu, 08 Jan 2009 19:51:19 UT

Hi all
I'm currently reading "Vicious Circles" by Barwise and Moss, and am
stuck on a proof in Chapter 11, on modal logic. This is the first
thing I've read about modal logic, so I apologise if my question
appears stupid. I'll also give a bit of background since I have no
idea how standard the authors' definitions and notations are: the

Multi input Weiner Filter

gyansor...@gmail.com (HardySpicer) — Thu, 08 Jan 2009 19:21:21 UT

For the standard SISO Wiener filter we minimize the cost J
J=E[e^2]=E(d-W'X)^2
where W is a vector of weights and X is a vector of regressers. (d is
desired output) Also ' denotes transpose.
We do this by diferentiating wrt the weight vector W and arrive at the
standard Wiener solution.
However, in the case where W is asymmetric Matrix and d is a vector

Symposium “Image Processing and Visualization in Solid Mechanics Processes” within the ESMC2009 Conference – Announce & Call for Papers

tava...@fe.up.pt (tavares@fe.up.pt) — Thu, 08 Jan 2009 15:24:29 UT

------------------------------ ------------------------------ ------------------------------ ------------------------------ ---------------------
(Apologies for cross-posting)
Symposium on “Visualization and Human-Computer”
7th EUROMECH Solid Mechanics Conference (ESMC2009)
Instituto Superior Técnico, Lisbon, PORTUGAL, September 7-11, 2009

Probability & combination question

petertwoca...@googlemail.com — Thu, 08 Jan 2009 15:13:51 UT

I'm having trouble knowing which methods I should be using to solve
this question:
(assume any other factors have no bearing on these simple
probabilities)
From the whole population if we found the probability of someone
having blonde hair = 0.2 & P(not blonde) = 0.8
If I pick a random group of 10 people, how to I work out the

how to calculate e^ix ?

azeez...@gmail.com (Nimo) — Thu, 08 Jan 2009 14:46:27 UT

Write sum of the terms in e^ix form as you like
for example I'm writing like this
(e^ix+e^i35x+e^-4x) x (e^i22x-e^i4x+e^i5x) x....( )..x.....
by multiplying by first 2 terms we will get 6 terms
if number of terms are more we will get more and more terms.
how to calculate them easily.
cos c + cos d &

Sale Nike Adidas Gucci Puma D&G Bape A&F NFL Watch (world famous brand)

cicitrade10...@yahoo.cn — Thu, 08 Jan 2009 13:37:14 UT

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We are supplier in china Footwear Apparel Handbags Jeans&Pants Cap
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compact sets

oer...@yahoo.com (oercim) — Thu, 08 Jan 2009 13:12:45 UT

Hello. What is a compact set? What is an intuitive explanation of
compact set? I cant understand the below definition:
"An open cover for a set S, inside a topological space T, is a
collection of open sets whose union contains S. A finite subcover is
any finite subcollection of these open sets whose union also contains

Perpendicular bisector question

newbar...@gmail.com — Thu, 08 Jan 2009 12:37:20 UT

I'm having problems with my linear algebra again. Here's the question:
"Find the equation of the perpendicular bisector of the line joining
the points (a,b) and (2a,-3b)"
The answer in the book is 8by - 2ax + 8b^2 + 3a^2 = 0.
My progress on it:
The perpendicular bisector must go through the mid point of the line